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a fost răspuns

c) (radical3+radical2)(radical3-radical2)
d) (2rasical3+3radical2)(2radical3-3radical2)
e)(radical2x+radical3y)(radical2x-radical3y)

Răspuns :

Pitiandrei
c ) ( √3 + √2 ) ( √3 - √2 ) = √9 - √6 + √6 - √4 = 3 - 2 = 1
d ) ( 2√3 + 3√2 ) ( 2√3 - 3√2 ) = 4√9 - 6√6 + 6√6 - 9√4 = 12 - 18 = -6
e)  ( √2x + √3y ) ( √2x - √3y ) = √4x^2 - √ 6xy + √6xy - √9y^2 = 2x - 3y 

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