Răspuns :
a) x(x-2)+x(3-x)=
[tex] x^{2} [/tex] -2x+3x-[tex] x^{2} [/tex]=
-2x+3x=x
b) 3(1-2a)+2(3a+1)=
3-6a+6a+2=
=5
[tex] x^{2} [/tex] -2x+3x-[tex] x^{2} [/tex]=
-2x+3x=x
b) 3(1-2a)+2(3a+1)=
3-6a+6a+2=
=5