22 1/3 = (22×3+1)/3 = 67/3
10 7/12 = (10×12+7)/12 = 127/12
9 11/20 = (9×20+11)/20 = 191/20
22 1/3 - (10 7/12 +9 11/20) =
= 67/3 - (127/12 + 191/20) =
= 67/3 - (127×5/60 + 191×3/60) =
= 67/3 - (635/60 + 573/60) =
= 67/3 - 1208/60 =
= 67×20/60 - 1208/60 =
= (1340 - 1208)/60 =
= 132/60 =
= 22/10 =
= 11/5 =
= 2 intregi 1/5
