4. Se da:
apa
t1=20*C
t2=80*C
c=4190J/kg**C
Q=492,6kJ=492600J
____________
m - ?
Re-re:
Q=cm(t2-r1)
m=Q/c(t2-t1)=492600/4190*60=1,95kg
5. Se da:
Lu=90,8MJ=90,8*10^6 J
benzina
V=10l=10dm3=0,01m3
p=700kg/m3
q=46*10^6J/kg
________
n-?
Re-re:
n=Lu/qm=Lu/qpv=90,8*10^6/46*10^6*700*0,01=0,28
n%=0,28*100%=28%
