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a fost răspuns

REPEDEEE VA ROGGG FRUMOSS! DAU COROANA!
Calculati: ( 2√2 + √3/2 - 1/√3 - 5/√2) : (1/√2 -1/2√3)
(2√2 NU este deasupra liniei de fractie)


Răspuns :

Pasul 1
[tex]2 \sqrt{2} + \frac{ \sqrt{3} }{2} - \frac{1}{ \sqrt{3} } - \frac{5}{ \sqrt{2} } [/tex]
_________________________(supra)
[tex] \frac{1}{ \sqrt{2} } - \frac{1}{2 \sqrt{3} } [/tex]
Pasul2
[tex]2 \sqrt{2} + \frac{ \sqrt{3} }{2} - \frac{ \sqrt{3} }{3} - \frac{5 \sqrt{2} }{2} [/tex]
______________________________(supra)
[tex] \frac{ \sqrt{2} }{2} \frac{ \sqrt{3} }{6} [/tex]
Pasul3
[tex] - \frac{ \sqrt{2} }{2} + \frac{ \sqrt{3} }{6} [/tex]
___________________________(supra)
[tex] \frac{ \sqrt{2} }{2} - \frac{ \sqrt{3} }{6} [/tex]
pasul 4
[tex] - ( \frac{ \sqrt{2} }{2} - \frac{ \sqrt{3} }{6} )[/tex]
___________________(supra)
[tex] \frac{ \sqrt{2} }{2} - \frac{ \sqrt{3} }{6} [/tex]
Si raspunsu final este:-1