Răspuns :
{a,b,c} dp {2,3,5}
a/2=b/3=c/5=k
a/2 = k --> a = 2k.
b/3 = k --> b = 3k.
c/5 = k --> c = 5k.
a²+b² = 52
4k²+9k² = 52
13k² = 52
k² = 52/13
k² = 4
k = (±)2.
N = b²+c²
N = 9k²+25k²
N = 9·2²+25·2²
N = 9·4+25·4
N = 36+100
N = 136.
a/2=b/3=c/5=k
a/2 = k --> a = 2k.
b/3 = k --> b = 3k.
c/5 = k --> c = 5k.
a²+b² = 52
4k²+9k² = 52
13k² = 52
k² = 52/13
k² = 4
k = (±)2.
N = b²+c²
N = 9k²+25k²
N = 9·2²+25·2²
N = 9·4+25·4
N = 36+100
N = 136.
a/2=b/3=c/5=k
a=2k
b=3k
c=5k
a²+b²=52
(2k)²+(3k)²=52
4k²+9k²=52
13k²=52
k²=4
k=√4
k=2
a=2k=2×2=4
b=3k=3×2=6
c=5k=5×2=10
N=b²+c²=6²+10²=36+100=136