Răspuns :
a+b=10 si b+c=12
3×a + 7 × b + 4×c= 48
=3 × a + 3 × b + 4 × b + 4×c=
= 3 × ( a + b) + 4 × (b + c)=
= 3×10 + 4×12=
=30 +48=
=78
Am descompus pe 7×b=3×b+4×b; apoi am dat factor comun!
3×a + 7 × b + 4×c= 48
=3 × a + 3 × b + 4 × b + 4×c=
= 3 × ( a + b) + 4 × (b + c)=
= 3×10 + 4×12=
=30 +48=
=78
Am descompus pe 7×b=3×b+4×b; apoi am dat factor comun!
a+b=10 |×3
b+c=12 |×4
3×a+7×b+4×c=?
___________
3×a+3×b=30
4×b+4×c=48
Le adunam ...
3×a+7×b+4×c=30+48=78
b+c=12 |×4
3×a+7×b+4×c=?
___________
3×a+3×b=30
4×b+4×c=48
Le adunam ...
3×a+7×b+4×c=30+48=78