Răspuns :
A'B = M√2 (M-muchia)
A(BCD'A')=25√2=M·M√2=M²√2=>M²=25√2/√2=>M=√25=5 dm
At=6·L²=6·5²=6·25=150 dm²
A(BCD'A')=25√2=M·M√2=M²√2=>M²=25√2/√2=>M=√25=5 dm
At=6·L²=6·5²=6·25=150 dm²