[tex] \frac{3(x + 1)}{3} = \frac{5(1 - x)}{5} - \frac{2(3x - 2)}{6} + 2[/tex]
[tex]x + 1 = 1 - x - \frac{3x - 2}{3} + 2[/tex]
[tex]2x - 2 = -\frac{3x - 2}{3} [/tex]
[tex]3 \times (2x - 2) = -(3x - 2)[/tex]
[tex]6x - 6 = -3x + 2[/tex]
[tex]9x = 8[/tex]
[tex] x = \frac{8}{9} [/tex]
