Răspuns :
In suma 2+4+6+...+4020 se da factor comun 2.
b = 2(1+2+3+....+2010) - 2010
In paranteza se aplica suma lui Gauss
b = 2 * 2010 * 2011 : 2 - 2010 = 2010*2011 - 2010. Se da factor comun 2010.
b = 2010(2011 - 1)
b = 2010 * 2010 = 2010^2 , care este patrat perfect.
b = 2(1+2+3+....+2010) - 2010
In paranteza se aplica suma lui Gauss
b = 2 * 2010 * 2011 : 2 - 2010 = 2010*2011 - 2010. Se da factor comun 2010.
b = 2010(2011 - 1)
b = 2010 * 2010 = 2010^2 , care este patrat perfect.
b=2+4+6....+4020-2010
b=2(1+2+..+2010)-2010
b=2·2010·2011:2-2010
b=2010·2011-2010
b=2010(2011-1)
b=2010·2010
b=2010²
b=2(1+2+..+2010)-2010
b=2·2010·2011:2-2010
b=2010·2011-2010
b=2010(2011-1)
b=2010·2010
b=2010²