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3^2-2^48÷(2^4×2^11)^3+1^2017+(2^2×3^2)÷(2×3)

Răspuns :

Didi12342
3^2-2^48÷(2^4×2^11)^3+1^2017+(2^2×3^2)÷(2×3) =

= 9-2^48:(2^15)^3 + 1 + (4 × 9) : 6 =

= 9 - 2^48 : 2^45 + 1 + 36 : 6 =

= 9 - 2^3 + 1 + 6 =

= 9 - 8 + 7 =

= 8

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