Răspuns :
x-elevi
y-banci
2(y-3)=x-1, 2y-x=5 x=2y-5
3(y-6)=x , 3y-x=18
3y-2y+5=18
y=13 banci
x=26-5=21 elevi
y-banci
2(y-3)=x-1, 2y-x=5 x=2y-5
3(y-6)=x , 3y-x=18
3y-2y+5=18
y=13 banci
x=26-5=21 elevi
e-nr de elevi
b-nr de banci
e=3*(b-6) stau cate 3 in B-6 banci
e=2(b-3)+1 stau cate 2 in b-3 banci si intr-o banca 1 elev
egalam si ⇒ 3b-18=2b-6+1
3b-2b=18-5
b=13 si e=3*(13-6)=21
b-nr de banci
e=3*(b-6) stau cate 3 in B-6 banci
e=2(b-3)+1 stau cate 2 in b-3 banci si intr-o banca 1 elev
egalam si ⇒ 3b-18=2b-6+1
3b-2b=18-5
b=13 si e=3*(13-6)=21