1330 : n = c1 rest 10, 1330=c1*n+10, 1330-10=n*c1 , conditia e ca n>10
350 :n = c2 rest 14 , 350 = c2*n+14, 350-14=n*c2, n>14
1320=n*c1
336=n*c2
rezulta ca n e un divizor comun al nr 1320 si 336 care respecta conditia n>14
calculez (1320,336)
1320=2^3*3*5*11
336=2^4*3*7
(1320,336)=2^3*3=24
rezulta ca n=24
