Răspuns :
ab+ac=145
a=5
5b+5c=145
5(b+c)=145
b+c=145:5
b+c=29
b=14
c=15
5*14+5*15=145
a=5
5b+5c=145
5(b+c)=145
b+c=145:5
b+c=29
b=14
c=15
5*14+5*15=145
daca a=5, iar numerele sunt consecutive, atunci ele sunt 57+58=115