(2/√2)⁻¹-(2√2)⁻¹]²·{[(√2+1)/(√2-1)]⁻¹-[(√2-1)/(√2+1)]⁻¹}=
[√2/2-1/2√2]²·[(√2-1)/(√2+1)-(√2+1)/(√2-1)]=
[(√4--1)/2√2]²·{[(√2-1)(√2-1)-(√2+1)(√2+1)]/(√2-1)(√2+1)}=
[(2-1)/2√2]²·{[(2-2√2+1)-(2+2√2+1)]/(2-1)}=
(1/2√2)²·[(3-2√2-3-2√2)/1]=
(1/8)·(-4√2)=-4√2/8=-√2/2
