a+b+c = 366
b : a = 2 rest 7 ==> b = 2×a+7
c : b = 2 rest 2 ==> c = 2×b+2
a |____|
b |____|____|+7
c |____|____|____|____|+2
366 - (7+2) = 366 - 9 = 357
357 : 7 = 51 (un segment egal)
a = 51
b = 2×51+7 = 102 + 7 = 109
c = 4×51+2 = 204+2 = 206
Verificare:
51 + 109 + 206 = 366