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calculati:2,6xy-2,(3)xy+1,(6)xy+(2,3xy-0,9xy)=...

Răspuns :

2,6xy - 2,(3)xy + 1,(6)xy + (2,3xy - 0,9xy)=
2,(3)=(23-2)/9=21/9=7/3
1,(6)=(16-1)/9-15/9=5/3
2,6xy - 7xy/3 + 5/3xy + 1,4xy=
4xy - 2xy/3=
(12xy-2xy)/3=
10xy/3
Icecon2005
2,6xy-2,(3)xy+1,(6)xy+(2,3xy-0,9xy)=.2,6xy-2,(3)xy+1,(6)xy+1,4xy=
=
=2,6xy-21xy/9+15xy/9+1,4xy

=[(2,6×9)xy-21xy+15xy+1,4×9]/9

=[ 23,4xy-21xy+15xy+12,6xy]/9

= 30xy/9

=10xy/3