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Calculati:
a) 5(x³ - 2x + 4) - 2(x³ - 2x + 4) - 3(x³ - 2x + 4) =
b) 3(x² + 2x - 3) - (3x² + 6x - 9) =
c) 7x (x+1) - 3x (x-1) - 2x =
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Răspuns :

Didi12342
a) 5(x³ - 2x + 4) - 2(x³ - 2x + 4) - 3(x³ - 2x + 4) =

= (X^3-2X+4) (5 - 2 -3) =

= (X^3 -2X+4) × 0 =

= 0


b) 3(x² + 2x - 3) - (3x² + 6x - 9) =
= 3(X^2 + 2X - 3) - 3(X^2 + 2X - 3) =
= (X^2 + 2X - 3)(3 - 3) =
= (X^2 + 2X-3) × 0 =
= 0

c) 7x (x+1) - 3x (x-1) - 2x =
= 6X^2 + 6X - 3X^2 + 3X - 2X =
= 3X^2 +7X =
= X(3X + 7)

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