pH+pOH = 14 => pOH = 2
LiOH -> B.T => [LiOH] = C = [OH⁻] = 10⁻(pOH) = 10⁻² M
MLiOH = 24g/mol
C = md/M*Vs sau C = n/Vs
C = md/M*Vs => md = C*M*Vs = 0,01*24*1,7 = 0,408g LiOH
C = n/Vs => n = C*Vs = 0,01*1,7 = 0,017 moli LiOH
n = m/M => m = n*M = 0,017*24 = 0,408g LiOH
