a+b+c = 365
a = 2b/3
c = a:2 + 47 = 2b/6+47
inlocuim in prima ecuatie in functie de b
2b/3 + b + 2b/6 + 47 = 365 |×6
4b + 6b + 2b + 282 = 2 190
12b = 2 190 - 282
12b = 1 908
b = 1 908 : 12
b = 159
a = 2×159/3 = 2×53 = 106
c = 106 : 2 + 47 = 53 + 47 = 100
Verificare:
106 + 159 + 100 = 365
a = 106
b = 159
c = 100
