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Rezolvati in R:
x (√3-1)-3√3=2 (x-3)(√3+1)-√27

Răspuns :

Iakabcristina2
x√3-x-3√3=2(x√3+x-3√3-3)-3√3
x√3-x=2x√3+2x-6√3-6
x√3-x-2x√3-2x+6√3+6=0
-x√3-3x+6√3+6=0
x(√3+3)=6(√3+1)
x=[6(√3+1)]/(√3+3)
x=[6(√3+1)(√3-3)]/(-6)
x=-(√3+1)(√3-3)
x=-(3-3√3+√3-3)
x=2√3
x√3-x-3√3=(2x-2·3)(√3+1)-3√3
x√3-x-3√3=2x√3+2x-6√3-6-3√3
-3√3+6√3+6+3√3=2x√3-x√3+2x+x
6√3+6=x√3+3x
6√3+6=x(√3+3)
x=6(√3+1)/(√3+3)
x=6(√3+1)(√3-3)/(√3+3)(√3-3)
x=6(3-3√3+√3-3)/(3-9)
x=6(-2√3)/(-6)=2√3

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