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33yoana
a fost răspuns

Descompuneti in factori:
a)(x+1)^2-4=
b)(x+2y)^2-(2x-y)^2=
c)(3a-4)^2-1=
d)(x-5)^2-(2x)^2=
f)9x^2-(3x-2)^2=
g)(2x-3)^2-9=
h)(y-4x)^2-(2x+5y)^2=
i)(x+3y-1l^2-(x-2y+1)=

Răspuns :

Bogdanclaudiu7
A) (x+1)^2-4= (x+1)^2 - 2^2 = [(x-1)+2][(x-1)-2] 
B) (x+2y)^2-(2x-y)^2= [(x+2y)+(2x-y)][(x+2y)-(2x-y)]
C) (3a-4)^2-1=[(3a-4)+1][(3a-4)-1]
D) ...=[(x-5)+2x][(x-5)-2x]
Ii exact la fel si la celalate numai ca inlocuiesti 

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