Notam cu a,bc numerele
a+b+c = 68
a = b-5 => b = a+5
a = 3×c
a |___|___|___|
b |___|___|___|+5
c |___|
avem 7 segmente egale +5 = 68
68 - 5 = 63
63 : 7 = 9 ( un segment)
a = 3×9 = 27
b = 3×9+5 = 27+5 = 32
c = 9
Verificare:
27+32+9 = 68
27=32-5
27= 37
Numerele sunt:
27; 32; 9.
