Răspuns :
Răspuns:
FALS
Explicație pas cu pas:
fie x=π/6
π/6+π/6=π/3
π/3-π/6=π/6
sin(π/3)+cos(π/6)=√3/2+√3/2=√3≠1
deci ai ceva GRESIT in tezxt
fie sunt la patrat, fie e o ecuatie de rezolvat
sin(x+pi/6)+cos(pi/3-x)
sin(x)cos(pi/6)+cos(x)sin(pi/6)+cos(pi/3)cos(x)+sin(pi/3)sin(x)
sin(x)×√3/2+cos(x)×1/2+1/2×cos(x)+√3/2×sin(x)
2sin(x)×√3/2+2cos(x)×1/2
sin(x)×√3+cos(x)
√3×sin(x)+cos(x)