trapezul este isoscel cu baza mare DC si baza mica AB
coborim inaltimea AH pe baza mare DC
[tex]DM= \frac{DC-AB}{2}= \frac{66-30}{2}=18cm
[/tex]
[tex]AH= \sqrt{AD^2-DH^2}= \sqrt{30^2-18^2} = 24cm \\ A= \frac{AB+DC}{2}*AH= \frac{30+66}{2}*24=48*24= 1152cm^2[/tex]
