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lim 3x+2/4x+6, x->infinit

Răspuns :

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[tex]\displaystyle \lim_{x \to \infty} \frac{3x+2}{4x+6} = \lim_{x \to \infty} \frac{x(3+ \frac{2}{x}) }{x(4+ \frac{6}{x} )} = \lim_{x \to \infty} \frac{3+ \frac{2}{x} }{4+ \frac{6}{x} } = \frac{3}{4} [/tex]

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