(a+b+c);3=121 =>a+b+c=121x3
a+b+c=363
a=30%b
a=3b/10
b/1/3=c/1/10=k
3b=10c=k
b=3k =>a=3x3k/10=9k/10
c=10k
le adunam
9k/10+3k+10k=363
numitor comun 10
9k/10+30k/10+100k/10=3630/10
inmultim cu 10
139k=3630
k=3630/139
a=9x3630/139 totul pe 10
a=32670/139x1/10
a=3267/139
b=3x3630/139
b=10890/139
c=10x3630/139
c=36300/139
nu cred ca e bime scris exercitiul!!!!!!!!
