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Alexaradoi98
a fost răspuns

Cu ce masa de Mg reactioneaza 200 g acid propanoic de puritate 74%?

Răspuns :

0,74*200=148g

n=m/M=148/74=2 moli acid

2CH3-CH2-COOH + Mg => (CH3-CH2-COO)2Mg + H2

2 moli acid.........24g Mg
2 moli acid.........24g Mg