Fe+2HCl=FeCl₂+H₂
c=md*100/ms⇒md=c*ms/100
md=30*300/100
md=90g HCl
Masa molara HCl=1+35.5=36.5g/mol
x=masa de Fe reactionata
x=90*56/2*36.5
x=69.04g Fe
gaz=H₂
y=mas de H₂ rezultata
y=90*2/2*36.5
y=2.46g H₂
1mol.....................2g H₂
z moli...................2.46
z=2.46*1/2=1.23moli H₂
1mol..........................22.4L H₂
1.23moli.....................w
w=1.23*22.4/1=27.552L H₂
