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2+4+6...+222=? dau coroana si foarte repede

Răspuns :

MariaDN
S=2+4+6+...+222
S= 2(1+2+3+4+...+111)
S= 2 × [tex] \frac{111*112}{2} [/tex]
S=2×[tex] \frac{12432}{2} [/tex]
S=2 ×6216
S=12432
[tex]\displaystyle 2+4+6+...+222=2(1+2+3+...+111)=\not2 \cdot \frac{111(111+1)}{\not2} = \\ \\ =111 \cdot 112=\boxed{12432}[/tex]

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