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PORUMBEL2016
a fost răspuns

calculați [3^3×3^45+3^100÷(3^72×3^3)+(2^2-1) ^48÷3^45

Răspuns :

Dddl
[3^3×3^45+3^100÷(3^72×3^3)+(2^2-1) ^48÷3^45=7.9766443e+22
[3³x3⁴⁵+3¹⁰⁰:(3⁷²x3³)+(2²-1)⁴⁸:3⁴⁵]=
[3⁴⁸+3¹⁰⁰:3⁷⁵+3⁴⁸:3⁴⁵]=
3⁴⁸+3²⁵+3³

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