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Manyup99
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Se alchileaza 780 kg benzen cu etena.Se obtine un amestec de etilbenzen,dietilbenzen si benzen in raport molar 5 : 0.5 : 1 .Cantitatea de etilbenzen care se obtine este:
a)6,82 kmoli
b)7,69 kmoli
c)815,38 kg

Răspuns :

Moonlight01
n=m/M=780/78=10 kmoli C6H6

x.................x..............................x
C6H6 + CH2=CH2 ===> C6H5-CH2-CH3
y...................2y............................y
C6H6 + 2CH2=CH2  ===> C6H4-(CH2-CH3)2 
z......................z
C6H6 ===> C6H6

x/y=5/0,5 =>y=0,5x/5 => y=0,5*7,6923/5=0,76923 kmoli dietilbenzen

x/z=5/1=>z=x/5 => z=7,6923/5=1,53846 kmoli C6H6

x+0,5x/5+x/5 = 10 => 6,5x/5=10 => x=50/6,5=7,6923 kmoli etilbenzen

R: b) 7,69 kmoli etilbenzen

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