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Adrianaalb
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2(x+3)≥5x-9
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Răspuns :

Baiatul122001
2(x+3)≥5x-9⇔2x+6≥5x-9⇔2x-5x≥-9-6⇔-3x≥-15⇒x≥-15/-3⇒x≥5⇒x∈[5;+∞)
2x+6≥5x-9
9+6≥5x-2x
15≥3x
x≤15/3
x≤5

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