x=numar bile albe
y=numar bile rosii
z=numar bile negre
a)x= 30/100* (x+y+z)
y=20/100 *x
z=32
Avem 2 relatii cu doua necunoscute deci putem rezolva sistemul:
x=3/10*x+3/10*y+3/10*z
x=3/10*x+3/10*20/100*x+3/10*32\\
x=3x/10+3x/50+96/10 |*50
50x=15x+3x+480
50x=18x+480
32x=480⇒x=15 bile albe
y=1/5*15 =3 bile rosii
b)x=15 bile albe⇒15 cazuri favorabile
x+y+z=50 bile⇒50 cazuri posibile
P=15/50 = 3/10
c) 3= 15a/100
300=15a
a=20 %