p=93%
p=mpur/mipur*100==>mpur=mimpur*p/100=372g CuCO3 pur
MCuCO3=ACu+AC+3AO=64+12+3*16=124g/mol
MHCl=AH+ACl=1+35.5=36.5g/mol
MCuCl2=135g/mol
124g.........73g.........135g......44g.....18g
CuCO3 + 2HCl -->CuCl2 + CO2 + H2O
372g......x=219g....y=405g....z=132g...w=54g
a) Cp=md/ms*100==>ms=md*100/Cp=219*100/36.5=600g sol. HCl
b) n=m/M=132/44=3 moli CO2
n=V/Vmolar==>V=n*Vmolar=3*22.4=67.2L CO2
c) n=m/M=405/135=3 moli CuCl2 (sarea rezultata)
