Răspuns :
1.
BC=AC
AB=8√6
∡C=90
pitagora
AB=BC√2
8√6=BC√2
BC=8√3
ariatr. At
At=BC^2 /2 = 64 x 3/2
At=96
2.
ducem BD⊥prelungirea lui CA
tr BDA dreptunghic in D, ∡BAD=30° ⇒ BD=AB/2 ⇒BD=6/5
aria At
At = AC x BD/2=5 x 6/10 = 3
a. Calculezi BC SI AC
AB^2=2BC^2
64*6=2BC^2
AC=BC=8RAD(3)
A=AC*BC/2=8*8*3/2=32*3=96
AB^2=2BC^2
64*6=2BC^2
AC=BC=8RAD(3)
A=AC*BC/2=8*8*3/2=32*3=96