Fie a si b masurile celor doua unghiuri.
Unghiuri suplementare⇒a+b=180°
(a,b) i.p. (0.25;0.2) (invers proportionale, eu asa notez, poate ai alte notatii cu {})
0.25=25/100=1/4
0.2=2/10=1/5
Din (a,b) i.p. (0.25;0.2) ⇒(a,b) i.p. (1/4;1/5) ⇒a·1/4=b·1/5=k, coeficient de proportionalitate⇒a/4=b/5=k
a/4=k⇒a=4k
b/5=k⇒b=5k
a+b=180°⇒4k+5k=180°⇒9k=180°⇒k=20°
a=4k=4·20°=80°
b=5k=5·20°=100°
