Răspuns :
g=3r-4
h=2r+4
h²=g²-r²
(2r+4)²=(3r-4)²-r²
4r²+16r+16=9r²-24r+16-r²
4r²+16r=8r²-24r
4r²=40r :4r
r=10 cm
g=3×10-4=26 cm
h=2×4+4=12 cm
Al=πrg=π×10×26=260π cm²
h=2r+4
h²=g²-r²
(2r+4)²=(3r-4)²-r²
4r²+16r+16=9r²-24r+16-r²
4r²+16r=8r²-24r
4r²=40r :4r
r=10 cm
g=3×10-4=26 cm
h=2×4+4=12 cm
Al=πrg=π×10×26=260π cm²
generatoarea G
G=3R-4
inaltimea h
h=2R+4
cu pitagora gasim relatia dintre G,h,R
G^2 = h^2+R^2
(3R-4)^2 = (2R+4)^2 + R^2 ridicam la patrat si reducem termenii asemenea
4R^2 - 40R = 0
de aici retinem solutia convenabila
R=10
G=26
aria laterala Al
Al=πRG = π x 10 x 26
Al=260π