MFe=56g/mol
MFeCl3=162.5g/mol
n=m/m=112/56=2 moli Fe
2 moli...3moli.....2moli
2Fe + 3Cl2 =>2FeCl3
2 moli....3moli....2 moli
112g.....106.5g......325g
112g......106.5g......x=71012.5g/218.5=325g FeCl3
sau
n=m/M =>m=n*M=2*162.5=325g FeCl3
g. 2FeCl3 + 3H2O --> Fe2O3 + 6HCl