Pentru ecuatia : [tex] x^{2} -(2m+1)x+3m=0,avem, x_{1}+ x_{2} =S=- \frac{b}{2a}= \frac{2m+1}{2},si, x_{1} x_{2}= [/tex][tex]P= \frac{c}{a}=3m,deci, x_{1} x_{2} + x_{1} + x_{2}=P+S=3m+ \frac{2m+1}{2}=11 [/tex]. Obtinam ecuatia:
6m+2m+1=22, deci m= 21/8
