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descompuneti in factori

a)x²+3x+2
b)x²+5x+4
c)x²+7x+12
d)x²+6x+8
e)x²+9x+14
f)x²+10x+21

dau coroana si 19 puncte

Răspuns :

Doralazz
a)x²+x+2x+2=x(x+1)+2(x+1)=(x+1)(x+2)
b)x²+x+4x+4=x(x+1)+4(x+1)=(x+1)(x+4)
c)x²+3x+4x+12=x(x+3)+4(x+3)=(x+3)(x+4)
d)x²+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)
e)x²+2x+7x+14=x(x+2)+7(x+2)=(x+2)(x+7)
f)x²+3x+7x+21=x(x+3)+7(x+3)=(x+3)(x+7)

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