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ce volum ocupa la 327 grade C si 300atm, 2800kg azot molecular? ....multumesc

Răspuns :

folosim ecuatia de stare:
PV=nr.de moli×RT
P-PRESIUNE
V-VOLUM
R-PARAMETRU=0.0082
T-TEMPERATURA IN GRADE KELVINI
transformam T
T=327grC+273=600gr kelvini
nr de moli =2800/14=200kmoli
V=200×0.0082×600/300
V=400×0.0082=3.28mcubi

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