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Bucurmaria03
a fost răspuns

Dau coroana!!!descompuneti in factori 25(x-3)²-4(3x+1)²=?

Răspuns :

Spidie
25(x-3)²-4(3x+1)²=[ 5*(x-3)+2(3x+1)]*[5(3x+1)-2(3x+1)]=
=(5x-15+6x+2)*(5x-15-6x-2)= (11x-13)(-x-17)= -(11x-13)(x+17)
Iakabcristina2
Folosim formula de calcul prescurtat a²-b²=(a-b)(a+b)
25(x-3)²-4(3x+1)²=[5(x-3)+2(3x+1)][(5(x-3)-2(3x+1)]
                           =(5x-15+6x+2)(5x-15-6x-2)
                           =(11x-13)(-x-17)
                           =-(11x-13)(x+17)

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