Răspuns :
Notam: x-primul nr; y-al doilea nr; z-al treilea nr. x+y+z=370 x=2y y=3z =>x=2×3z (2×3z)+3z+z=370 6z+3z+z=370 10z=370 z=37 x=2×3×37=222 y=3×37=111 222+111+37=370
a)/.../.../.../.../.../.../
b/.../.../.../
c)/.../
b=3c
a=2b⇒=6c
c+3c+6c=10c
10c=370
c=270:10
c=37
b=37x3=111
a=37x6=222
b/.../.../.../
c)/.../
b=3c
a=2b⇒=6c
c+3c+6c=10c
10c=370
c=270:10
c=37
b=37x3=111
a=37x6=222