Răspuns :
adunam toate ecuatiile de mai sus
a+b+b+c+a+c= 100+427+481
(a+b+c) + (a+b+c)= 1008
a+b+c=1008 :2
a+b+c=504
a+b+b+c+a+c= 100+427+481
(a+b+c) + (a+b+c)= 1008
a+b+c=1008 :2
a+b+c=504
a + b = 100
b + c = 427
a + c = 481
2a + 2b + 2 c = 100 + 427 + 481
2 ( a + b + c ) = 1008
a + b + c = 1008 : 2
a + b + c = 504
100 + c = 504
c = 504 - 100
c = 404
a + c = 481
a + 404 = 481
a = 481 - 404
a = 77
a + b = 100
77 + b = 100
b = 100 - 77
b = 23
b + c = 427
a + c = 481
2a + 2b + 2 c = 100 + 427 + 481
2 ( a + b + c ) = 1008
a + b + c = 1008 : 2
a + b + c = 504
100 + c = 504
c = 504 - 100
c = 404
a + c = 481
a + 404 = 481
a = 481 - 404
a = 77
a + b = 100
77 + b = 100
b = 100 - 77
b = 23