Răspuns :
[tex]AC = d = 8 \: cm[/tex]
[tex]d = l \sqrt{2} = AB \sqrt{2} [/tex]
[tex]AB \sqrt{2} = 8[/tex]
[tex]AB = \frac{8}{ \sqrt{2} } [/tex]
[tex]AB = \frac{8 \sqrt{2} }{2} [/tex]
[tex]AB = 4 \sqrt{2} \: cm[/tex]
[tex]d = l \sqrt{2} = AB \sqrt{2} [/tex]
[tex]AB \sqrt{2} = 8[/tex]
[tex]AB = \frac{8}{ \sqrt{2} } [/tex]
[tex]AB = \frac{8 \sqrt{2} }{2} [/tex]
[tex]AB = 4 \sqrt{2} \: cm[/tex]
Pitagora
AC² = AB² + BC² si AB = BC
AC² = 2AB²
64 = 2AB²
AB = √64/2
AB = 8/√2
AB = 4√2 cm
AC² = AB² + BC² si AB = BC
AC² = 2AB²
64 = 2AB²
AB = √64/2
AB = 8/√2
AB = 4√2 cm