1mol 1mol
HCl + NaOH = NaCl + H2o
M,HCl = (1gH +35,5gCl)/mol= 36,5g/mol
M,NaOH= (23gNa+16gO+1gH)/mol=40g/mol
daca 36,5g acid reactioneza cu 40g baza
14,6g.........................................m ; m= 14,6x40/36,5g baza
m,NaOh= 16g---> escesul este (25-16)g NaOH CALCULEAZA !!!!