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Sall am si eu niste descompuneri in factori :
1. xy-x-y+1=
2. 9xy+3x-3y-1=
3.25x²-49=
4.x-2)²-4x²=
5.x²+6x+9-y²=
6.x²+7x+6=

Răspuns :

Deni00
1) Grupezi termenii:
x(y-1)-(y-1)=(y-1)(x-1)
2)3x(3y+1)-(3y+1)=(3y+1)(3x-1)
3)(5x-7)(5x+7)
4)(x-2-2x)(x-2+2x)=(-x-2)(3x-2)
5)(x+3)²-y²=(x+3-y)(x+3+y)
6)x²+7x+6=x²+6x+x+6=x(x+6)+(x+6)=(x+6)(x+1)