1mol 1mol 1mol
CH3-CH2Cl + HOH---.> CH3-CH2OH +HCl
2mol ............2mol...............2mol
M= 24gC+6gH+16gO= 46g/mol alcool; M=18g apa
m= 2molx46g/mol= 92g alcool---> este md in solutia formata
m=2molx18gapa=36g
masa de apa ramasa dupa ce a avut loc reactia. 708-36= 672gapa
c= mdx100/ms, unde ms= md+m,apa=> 92+672=768g solutie
c= 92x100/ 768=12% verifica !