[tex]f(x)=mx^2-(m+3)x+4[/tex]
[tex]mx^2-(m+3)x+4=0
a=m
b=-(m+3)
c=4
delta=b^2-4ac= (-(m+3))^2-4*m*4 = -m^2-6m-9+16m=
=-m^2+10m-9
[/tex]
Delta=0
[tex]-m^2+10m-9=0 /(-1)
m^2-10m+9=0
a=1
b=-10
c=9
delta=b^2-4ac= (-10)^2-4*1*9=100-36=64
[/tex]
[tex]m1= \frac{10+8}{2}= \frac{18}{2}=9 [/tex]
[tex]m2= \frac{10-8}{2}= \frac{2}{2}=1 [/tex]
